Monday, March 31, 2014

Array1 - Codingbat



packagetest.codingbat;

public class Array1 {
      
       // return true if first and last element of array is 6
       public boolean firstLast6(int[] nums) {
             
              int length = nums.length;
              final int number = 6;
                    
              if (nums[0] == number || nums[length-1] == number)
                     return true;
              else
                     return false;
       }
      
       // return true if first and last element of array is same
       public booleansameFirstLast(int[] nums) {
             
              if (nums.length == 0)
                     return false;
              else if (nums[0] == nums[nums.length-1])
                     return true;
              else
                     return false;
       }
      
       // return an integer array with value pi (3.14)
       public int[] makePi() {
             
              int[] pi = new int[]{3,1,4};
              return pi;
       }
      
       // return true if first or last elements of both arrays are same
       public boolean commonEnd(int[] a, int[] b) {
             
              if(a[0] == b[0] || a[a.length-1] == b[b.length-1])
                     return true;
              else
                     return false;
       }
      
       // return sum of the elements
       public int sum3(int[] nums) {
             
              int sum = 0;
              for (int i = 0; i < nums.length; i++) {
                     sum = sum + nums[i];
              }
              return sum;
       }
      
       // rotate elements to the left
       public int[] rotateLeft3(int[] nums) {
               
              int temp = 0;
              temp = nums[0];
              for (int i = 0; i < nums.length; i++) {
                     if(i==nums.length-1) break;
                     nums[i] = nums[++i];
                     --i;
              }
              nums[nums.length-1] = temp;
              return nums;
       }

      
       // return elements in reverse order
       public int[] reverse3(int[] nums) {
                int temp = nums[0];
                nums[0] = nums[nums.length-1];
                nums[nums.length-1] = temp;
                return nums;
       }
      
       // find largest between first and last element and set all elements to that value
       public int[] maxEnd3(int[] nums) {
              int largest = 0;
              largest = (nums[0] > nums[nums.length-1]) ? nums[0] : nums[nums.length-1];
              for(int i = 0; i < nums.length; i++) {
                     nums[i] = largest;
              }
              return nums;
       }
      
       // return the sum of the first 2 elements in the array.
       // If the array length is less than 2, just sum up the elements that exist,
       // returning 0 if the array is length 0. 
       public int sum2(int[] nums) {
             
              if (nums.length == 0 ) return 0;
              else if (nums.length == 1) return nums[0];
              else return nums[0] + nums[1];
               
       }
      
       // Given 2 int arrays, a and b, each length 3,
       // return a new array length 2 containing their middle elements.
       public int[] middleWay(int[] a, int[] b) {
                int newArray[] = new int[]{a[1],b[1]};
                return newArray;
       }
      
       // Given an int array, return a new array with double the length where its last element
       // is the same as the original array, and all the other elements are 0.
       // The original array will be length 1 or more.
       public int[] makeLast(int[] nums) {
                int length = nums.length;
                int newArray[] = new int[2*length];
                newArray[newArray.length-1] = nums[nums.length-1];
                return newArray;
       }






}

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